6x^2+3x-630=0

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Solution for 6x^2+3x-630=0 equation:



6x^2+3x-630=0
a = 6; b = 3; c = -630;
Δ = b2-4ac
Δ = 32-4·6·(-630)
Δ = 15129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15129}=123$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-123}{2*6}=\frac{-126}{12} =-10+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+123}{2*6}=\frac{120}{12} =10 $

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